Respuesta :
To find the wavelength of a neutron can be calculated by using the formula
Wavelength=h/m x v
Where h is planck's constant
m=mass of neutron
v= velocity of the particle
By substituting the given values
Wavelength= 6.63 × 10–34 j s / 1.675 × 10–27 kg x 2 m/s^-1
Wavelength of a neutron=1.979 x 10^-7 m
The wavelength of a neutron is 1.98 × 10⁻⁷ m
Further explanation
The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:
[tex]\large {\boxed {E = h \times f}}[/tex]
E = Energi of A Photon ( Joule )
h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )
f = Frequency of Eletromagnetic Wave ( Hz )
The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]
[tex]\large {\boxed {E = qV + \Phi}}[/tex]
E = Energi of A Photon ( Joule )
m = Mass of an Electron ( kg )
v = Electron Release Speed ( m/s )
Ф = Work Function of Metal ( Joule )
q = Charge of an Electron ( Coulomb )
V = Stopping Potential ( Volt )
Let us now tackle the problem!
This problem is about De Broglie's wavelength.
Given:
v = 200 cm/s = 2 m/s
m = 1.675 × 10⁻²⁷ kg
h = 6.63 × 10⁻³⁴ Js
Unknown:
λ = ?
Solution:
[tex]\lambda = \frac{h}{mv}[/tex]
[tex]\lambda = \frac{6.63 \times 10^{-34}}{1.675 \times 10^{-27} \times 2}[/tex]
[tex]\large {\boxed {\lambda \approx 1.98 \times 10^{-7} ~ m} }[/tex]
Learn more
- Photoelectric Effect : https://brainly.com/question/1408276
- Statements about the Photoelectric Effect : https://brainly.com/question/9260704
- Rutherford model and Photoelecric Effect : https://brainly.com/question/1458544
- Photoelectric Threshold Wavelength : https://brainly.com/question/10015690
Answer details
Grade: High School
Subject: Physics
Chapter: Quantum Physics
Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt
