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YukiH
I'm going to write < for angles:

We are given that <BOD = <COD and that <COB = 148 degrees

So we get 148/2 = 74 degrees for both <COD and <BOD.

You know a straight line is 180 degrees and that <COB is 148 degrees

Therefore, <AOC is 180 - 148 = 32 degrees

We solved for <COD and it was 74 degrees so we add it to the 32 degrees to get 106 degrees for <AOD.

Answer: 106° for ∠AOD
 
ashishdwivedilVT

∠AOD comes to be 106°.

It is given that

∠COB = 148°

∠BOD = ∠COD

Let us say ∠BOD = ∠COD = x

x+ x +148

x =74°

∠BOD = ∠COD = 74°

What will be the value of ∠AOB ?

∠AOB = 180°

So, ∠AOC + (∠COD + ∠BOD)= 180°

As we know that ∠COD + ∠BOD = ∠COB =148°

So, ∠AOC + 148 = 180

∠AOC = 180-148 = 32°

So, ∠AOD = ∠AOC + ∠COD

∠AOD = 32 + 74 = 106°

Therefore, ∠AOD comes to be 106°.

To get more about angles visit:

https://brainly.com/question/25770607

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