KeithBoutte1
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Let a and b be real numbers where a=b=0. Which of the following functions could represent the graph below?

f(x)=x(x-a)^3(x-b)^3
f(x)=(x-a)^2(x-b)^4
f(x)=x(x-a)^6(x-b)^2
f(x)=(x-a)^5(x-b)

Let a and b be real numbers where ab0 Which of the following functions could represent the graph below fxxxa3xb3 fxxa2xb4 fxxxa6xb2 fxxa5xb class=

Respuesta :

Answer:

Option: b is the answer.

( f(x)=(x-a)^2(x-b)^4 )

Step-by-step explanation:

Clearly from the graph of the function we could see that zero is not a root of the polynomial function hence option (a) ( f(x)=x(x-a)^3(x-b)^3 ) and option (c) (  f(x)=x(x-a)^6(x-b)^2 )are discarded.

Now we will check for option (b) and option (d)

As the graph touches the x-axis at two point i.e. a and b that means that both the roots of the polynomial equation are of even degree.

Hence, the correct option is:

option: b ( f(x)=(x-a)^2(x-b)^4 ).

It can be deduced that the option that represents the graph is B. f(x)=(x-a)²(x-b)⁴

How to solve the graph

From the graph, a and b be real numbers where a=b=0. In this case, zero is not a root of the polynomial function

When the graph touches the x-axis at two point l, it implies that means that both the roots of the polynomial equation are of even degree.

In conclusion, the correct option is B.

Learn more about graphs on:

https://brainly.com/question/25020109

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