Answer:
The period, in seconds to two decimal places is, 2.84 sec
Step-by-step explanation:
Using formula:
[tex]T = 2 \pi \sqrt{\frac{l}{g}}[/tex] ......[1]
where
T represents the Time period in second
l represents the length of the pendulum/
As per the statement:
Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and [tex]\pi = 3.14[/tex]
Substitute the given values we have;
[tex]T = 2\cdot 3.14 \cdot \sqrt{\frac{2}{9.8}}[/tex]
⇒[tex]T = 6.28 \cdot \sqrt{\frac{1}{4.9}}=6.28 \cdot \frac{1}{2.21359436212}= \frac{6.28}{2.21359436212} = 2.83701481512[/tex]
Therefore, the period, in seconds to two decimal places is, 2.84 sec
