Just as you look at it, the only factor common to all three terms is 'x'.
So you can factor the 'x' out and make the equation . . .
x (3x²-19x - 14) = 0
Right there, that tells you that [ x = 0 ] is a solution of the original equation.
But you're not looking for solutions, you're looking for factors, so you continue.
What about that ugly trinomial: [ 3x² - 19x - 14 ] ? Can that be factored ?
Not easily. But if you stuff it into the quadratic equation, you'll find two solutions
to the equation
3x² - 19x - 14 = 0
and you'll recall that (x - a solution) is a factor of the left side.
So you can find the remaining two factors of the original trinomial.
