Okay. So, there are 12 blue tickets and 20 red tickets, which makes 32 total tickets in the bag. 12/32 tickets in the bag are blue, and we can simplify that fraction. 12/32 is less than 1/2, so A and D are both eliminated. 12/32 is 3/8 simplified. There is 3/8 of a chance that a blue ticket will randomly be selected from the bag. The answer is C.
