Write the algebraic expression representing the length and width of Marliens house. Someone please tell me the process of how to do this

This is telling you to find out the dimensions of her house.
I suggest using mathpapa for each equation. It will show you how to solve it and then the answer.
So for the top dimensions, put the following into mathpapa: (2x-10)+(x-2)+(.5x-4)+(x-2)

Answer Link

erinna erinna · Answer 2 · 2020-03-07T04:00:38+01:00

Answer:

Length of Marliens house = [tex](\frac{7}{2}x-4)\text{ or }(\frac{9}{2}x-18)[/tex] .

Width of Marliens house = [tex](2x-2)[/tex].

Step-by-step explanation:

We need to find the length and width of Marlien's home in algebraic expressions.

Add length of living room, hallway and kitchen, to find the length of Marlien's home.

Length of Marlien's home = [tex](2x+2)+(\frac{1}{2}x-4)+(x-2)=\frac{7}{2}x-4[/tex]

Or we can add Master bedroom,guest room, hallway and bathroom, to find the length of Marlien's home.

Length of Marlien's home = [tex](2x-10)+(x-2)+(\frac{1}{2}x-4)+(x-2)=\frac{9}{2}x-18[/tex]

Add width of living room and Master bedroom to find the width of Marlien's home.

Width of Marlien's home = [tex]x+(x-2)=2x-2[/tex]

Hence, the length of Marliens house is either [tex](\frac{7}{2}x-4)\text{ or }(\frac{9}{2}x-18)[/tex] and width of Marliens house is [tex](2x-2)[/tex].