First let us see what kind of bonds are formed in the compound. By drawing the structure, we see that the kind of bonds are:
N =- triple bond -= C – O
So there is only single bond between C and O therefore the hybridization of C is sp.
Answer : The hybridization of carbon in [tex]NCO^-[/tex] is, [tex]sp[/tex] hybridized.
Explanation :
As we know that when a carbon attached to the four single sigma bonds then the hybridization will be, [tex]sp^3[/tex].
When a carbon attached to the three single sigma bonds and one-[tex]\pi[/tex] bond that means a carbon bonded to another atom by the double bond then the hybridization will be, [tex]sp^2[/tex].
When a carbon attached to the two single sigma bonds and two-[tex]\pi[/tex] bonds that means a carbon bonded to another atom by the triple bond then the hybridization will be, [tex]sp[/tex].
As per question, the given molecule is, [tex]NCO^-[/tex]. In this molecule, a triple bond is present between the nitrogen and carbon atom and a single bond is present between the carbon and oxygen atom. That means, a carbon bonded to another atom by the triple bond then the hybridization will be, [tex]sp[/tex].
Hence, the hybridization of carbon in [tex]NCO^-[/tex] is, [tex]sp[/tex] hybridized.
