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A trucking company needs to move a pile of limestone. The limestone is stored in a pile shaped like a cone. The pile is 13 yards high, and its base has a radius of 9 yards. How many truckloads will the company need, if each truck holds 7.03 yd³ of limestone?
Use 3.14 for π, and do not round your answer.

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audreyn06

Answer: 157 truckloads

Step-by-step explanation:

To calculate how many truckloads the company will need, we first need to calculate how many cubic yards of limestone there is.

We can calculate the volume of the limestone using the formula for the volume of a cone since the problem states that the pile is shaped like a cone. The formula for the volume of a cone is given as:

[tex]V = \frac{1}{3} \pi r^{2} h[/tex], where:

  • V represents the volume of the cone
  • r represents the radius of the base of the cone
  • h represents the height of the cone

The dimensions we are given are:

  • The radius (r) is 9 yards
  • The height (h) is 13 yards

Plugging these values into the formula and using 3.14 for π:

[tex]V = \frac{1}{3} (3.14)(9)^{2} (13)[/tex]

V = 1102.14 cubic yards of limestone

Since we have calculated the volume of the limestone, we need to calculate how many truckloads the company will need. To do this, we can divide the total amount of limestone by how much limestone each truckload holds.

It is given that each truckload holds 7.03 cubic yards of limestone.

1102.14 ÷ 7.03 = 156.7766714

Since it is not possible to have a fraction of a truckload, we need to round 156.7766714 up to the nearest integer.

Therefore, the company will need 157 truckloads.

Learn more about volume here: https://brainly.com/question/14197390

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