There are 20 children in the cast of a class play, and 8 of the children are boys. Of the boys, 4 have a speaking part in the play, and of the girls, 8 do not have a speaking part in the play. If a child from the cast of the play is chosen at random, what is the probability that the child has a speaking part?
a. 2/5
b. 1/2
c. 3/5
d. 3/4

4 girls and 4 boys have a speaking part, if you put that in fraction form you have 8/20 then all you do is divide 8 and 20 by 4 to simplify the answer to 2/5. The answer is a.2/5

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RajarshiG RajarshiG · Answer 2 · 2022-07-27T14:19:41+02:00

The probability that a child from the cast of the play is chosen at random has a speaking part out of 20 children is [tex]\frac{2}{5}[/tex].

What is the probability?

Probability of an event is the chance of happening that event.

Given, there are 20 children.

There are 8 boys.

Therefore, the number of boys is

[tex]= (20-8)\\= 12[/tex]

Out of 12 girls, 8 girls do not have a speaking part.

Therefore, the number of girls who have a speaking part is

[tex]= (12-8)\\= 4[/tex]

There are 4 boys and 4 girls who have a speaking part.

Hence, there are 8 children who has a speaking part.

Now, if a child from the cast of the play is chosen at random, then the probability that the child has a speaking part has a speaking part out of 20 children is

[tex]= \frac{8}{20}\\ = \frac{2}{5}[/tex]

Learn more about probability here: https://brainly.com/question/11234923

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