Answer:
x^2+x-6[/tex]
Explanation:
We have been given two zeroes x= -3 and x=2 of some quadratic equation
We have to find the quadratic equation when x=-3 is a zero means (x+3) is a factor and when x=2 is a zero means (x-2) is a factor
We have a formula to find the quadratic equation from zeroes is
[tex]x^2-(sum of zeroes )x+product of zeroes[/tex]
Here sum of zero is -3+2=-1
And product of zero is (-3)(2)=-6
substituting the values in the formula we will get
[tex]x^2 -(-x)+(-6)=x^2+x-6[/tex]
Answer:
y=[tex]x^{4}[/tex]+[tex]x^{3}[/tex]-[tex]5x^{2}[/tex]+x-6
