Let the smallest of the three odd integer be A. The next integer will be (A+2), and the largest of the three is (A+4)
Given: A + (A+2) + (A+4) = 123
Combine like terms and solve for A as follows
3A + 6 = 123Subtract 6 from each side of the equation to yield
3A = 117
Divide both sides by 3. Yields
A = 39
The sum of three consecutive odd integers is 123. Fd the integers.
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1st: 2n+1
2nd: 2n+3
3rd: 2n+5
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EQUATION:
2n+1 + 2n+3 + 2n+5 = 6n + 9 = 123
6n = 114
n = 19
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1st: 2*19+1 = 39
2nd: 41
3rd: 43
