Answer:
The solution is the attached figure
Step-by-step explanation:
we have
[tex]-5c+2\leq 27[/tex]
solve for c
[tex]-5c\leq 27-2[/tex]
[tex]-5c\leq 25[/tex] ------> Multiply by [tex]-1[/tex] both sides
[tex]5c\geq-25[/tex]
Divide by [tex]5[/tex] both sides
[tex]5c/5\geq-25/5[/tex]
[tex]c\geq-5[/tex]
The solution is the interval--------> [-5, ∞)
All real numbers greater than or equal to [tex]-5[/tex]
The solution is the attached figure
