Respuesta :
-np - 90 < 30
+ 90 + 90
-np < 120
p p
-n < 120/p
-1 -1
n < -120/p
5m - 3h < 45
5m - 5m - 3h < -5m + 45
-3h < -5m + 45
-3 -3
h < 1²/₃m - 15
+ 90 + 90
-np < 120
p p
-n < 120/p
-1 -1
n < -120/p
5m - 3h < 45
5m - 5m - 3h < -5m + 45
-3h < -5m + 45
-3 -3
h < 1²/₃m - 15
Answer: The required solutions are :
[tex](a)~n>-\dfrac{120}{p},~~~(b)~h=\dfrac{5m-45}{3}.[/tex]
Step-by-step explanation: We are given to solve the following :
(a) −np − 90 < 30 for n.
We have
[tex]-np-90<30\\\\\Rightarrow -np<30+90\\\\\Rightarrow -np<120\\\\\Rightarrow n>-\dfrac{120}{p}.[/tex]
(b) 5m − 3h = 45 for h.
We have
[tex]5m-3h=45\\\\\Rightarrow 3h=5m-45\\\\\Rightarrow h=\dfrac{5m-45}{3}.[/tex]
Thus, the required solutions are :
[tex](a)~n>-\dfrac{120}{p},~~~(b)~h=\dfrac{5m-45}{3}.[/tex]