Respuesta :
W = kL where W = weight supported, L = length of the beam and k is constant of variation.
Substituting the given values:-
310 = 2k
k = 155
so equation of variation is W = 155L
For length 10 m the weight it can support is
W = 155*10 = 1550 kg answer
Substituting the given values:-
310 = 2k
k = 155
so equation of variation is W = 155L
For length 10 m the weight it can support is
W = 155*10 = 1550 kg answer
Answer:
62 kg.
Step-by-step explanation:
Let w be the weight of beam and l be the length of beam.
We have been given that the weight that a horizontal beam can support varies inversely as the length of the beam.
We know that inversely proportion quantities are in form: [tex]y=\frac{k}{x}[/tex], where k is constant of proportionality.
[tex]w=\frac{k}{l}[/tex]
First of all, we will find the value of k using the [tex]w=310[/tex] and [tex]l=2[/tex] in inversely proportion equation as:
[tex]310=\frac{k}{2}[/tex]
[tex]310*2=\frac{k}{2}*2[/tex]
[tex]620=k[/tex]
Now we will substitute [tex]620=k[/tex] and [tex]l=10[/tex], in our given equation as:
[tex]w=\frac{620}{10}[/tex]
[tex]w=62[/tex]
Therefore, a 10-m beam can support 62 kilograms.
