Respuesta :
From ideal gas equation that is PV=nRT
n(number of moles)=PV/RT
P=760 torr
V=4.50L
R(gas constant =62.363667torr/l/mol
T=273 +273=298k
n is therefore (760torr x4.50L) /62.36367 torr/L/mol x298k =0.184moles
the molar mass of NO2 is 46 therefore density= 0.184 x 46=8.464g/l
n(number of moles)=PV/RT
P=760 torr
V=4.50L
R(gas constant =62.363667torr/l/mol
T=273 +273=298k
n is therefore (760torr x4.50L) /62.36367 torr/L/mol x298k =0.184moles
the molar mass of NO2 is 46 therefore density= 0.184 x 46=8.464g/l
Answer:
The nitrogen dioxide gas is 4.43 g/L.
Explanation:
Pressure of the of the gas = P = 760.0 torr = 2.356 atm
(1 torr = 0.00131 atm)
Volume of the tank = 4.50 L
Temperature of the gas = 25 °C = 298 K
Moles of gas = n = [tex]\frac{mass}{46 g/mol}[/tex]
Using an ideal gas equation:
[tex]PV=nRT[/tex]
[tex]\frac{P\times 46 g/mol}{RT}=\frac{Mass}{V}=Density[/tex]
[tex]Density=\frac{2.356 atm\times 46 g/mol}{0.0820 L atm/mol K\times 298 K}[/tex]
Density = 4.43 g/L
The nitrogen dioxide gas is 4.43 g/L.