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A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the box?

Respuesta :

leanarocks
Use this numbers that you are given and plug them into the formule for net force

Net force= m*a (mass times acceleration)

Therefore the net force is equal to (5.5 kg)*(4.2 m/s^2)= 23.1 N

Answer: Net force= 23.1 N

23.1N of force applied


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