The first term of an arithmetic sequence is 14, that is:
[tex]a_1=14[/tex]. Also, we are given that the common difference is 9, which means that each next term is obtained by adding 9, as follows:
[tex]a_1=14\\\\a_2=14+9\\\\a_3=(14+9)+9\\\\a_4=(14+9+9)+9\\\\...[/tex].
So we notice that to get the value of the n'th term, [tex]a_n[/tex], we must add (n-1) nines to 14.
(For example, to find the second term we added 1 nine to 14. To find the third term we added 2 nines to 14, and so on...)
Thus, [tex]a_{11}=14+9 \cdot 10=14+90=104.[/tex]
Answer: 104.
