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Adam had RM40.Susan gave 1 over 3 of her money to Adam .After giving 1 over 8 of his money to Gopal, Adam still had RM350. Find the total amount Susan had originally

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Ivka93
Adam had: RM40.
Susan had x money but she gave 1/3 of her money to Adam: x-1/3x+40=y
y-Adam's money after Susan gave his 1/3 of her's money.
After giving 1/8 of his money to Gopal, Adam still had RM350: y-1/8y=350
x-1/3x+40=y
y-1/8y=350⇒7/8y=350⇒y=400
2/3x+40=400⇒2/3x=360⇒x=540
Originally Susan had RM540.
W0lf93
Let x = Susan's money originally 
Let y = Adam's money before giving to Gopal
 From Adam and Susan's transaction:
 y = 40+(1/3)x
 From Adam and Gopal's transaction:
 350 = (7/8)y
 y = 400
 Adam has RM400 before giving to Gopal.
 400 = 40+(1/3)x
 x = 1080
 Therefore, Susan had RM1080 originally.

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