We are given with a compound, Nitric Acid (HNO3) solution,characterized as a strong acid. We are tasked to solve for it's corresponding mass pOH given [H+] = 3.26 x 10-6 moles/liter. Note that
14=pH+pOH
First we need to convert [H+] to pH by
pH=-log[H+]
pH=-log[3.26x10-6]
pH=5.49
Thus,
14=5.49+pOH
pOH=14-5.49=8.51
Therefore, the pOH of Nitric acid solution having a [H+] = 3.26 x 10-6 moles/liter is 8.51
8.51 would be the pOH of an HNo3 solution if the [H+] = 3.26 x 10^-6 moles/liter.
