The difference in the mean will be (μ1-μ2) = 27-29= -2
and the probability range is -3∠x∠ 3
Working with standard deviations for the half sets 30 and 30 for the two sets;
σ= √(( 8.3²/30)-(7.9²/30)
= 2.092
Thus, (-3-(-2))/2.092 ∠ x ∠ (3- (-2))/ 2.092
= -0.48 ∠ x ∠ 2.39
Probability = 1- normal cdf
Normal cdf = (-5, - 0.48) ∠ x ∠ (5, 2.39)
= 0.3156 ∠ р ∠ 0.9916
Therefore, probability = 0.9916 - 0.3156 =0.6760
Thus the probability will be equivalent to 0.6760