Respuesta :
He is 39 because 3+9=12, and next year he would be 40. 4+0=4, and 12 is 3 times larger than 4. He's old.
Solution:
we are given that
“If you add the digits that make my age this year, you’ll get a number three times bigger than if you do it next year.”
Let the first digit of the father's age be x and the second digit be y
Then we can write
[tex]x+y= 3(x + y + 1) \\ \\ x+y= 3(x + y) + 3\\[/tex]
[tex]3(x+y)-(x+y)=-3\\ \\ 2(x+y)=-3\\ \\ (x+y)=-3/2\\ \\[/tex]
Since [tex]x + y[/tex] cannot be negative,
So we can again write
[tex]x + y = 3(x + 1 + y - 9) \\ \\ x+y= 3(x + y - 8) \\ \\ x+y= 3(x + y) - 24[/tex]
[tex]2(x+y)=24\\ \\ x+y=12\\[/tex]
Hence age of the father is 39.