Answer:
Option (2) is correct.
s = 7 satisfy the given equation [tex]s=4+\sqrt{s+2}[/tex].
Step-by-step explanation:
Consider the given equation,
[tex]s=4+\sqrt{s+2}[/tex]
We have to solve for the value of s so that it satisfy the given equation
We first check for s = 2,
LHS = s = 2
RHS = [tex]4+\sqrt{s+2}[/tex]
Put s = 2 , we get ,
[tex]s=4+\sqrt{2+2}=4+\sqrt{4}=4+2=6[/tex]
we get LHS = 2 and RHS = 6 which are not equal.
Thus, s = 2 does not satisy the given equation.
We now check for s = 7
LHS = s = 7
RHS = [tex]4+\sqrt{s+2}[/tex]
Put s = 7 , we get ,
[tex]s=4+\sqrt{7+2}=4+\sqrt{9}=4+3=7[/tex]
we get LHS = 7 and RHS = 7 which are equal.
Thus, s = 7 satisfy the given equation [tex]s=4+\sqrt{s+2}[/tex].
