The length of the rope was [tex] \frac{6}{8} [/tex] yard
Jeff cut the rope into 3 pieces.
Each piece is a different length measured in eighths of a yard which means that the denominator of each piece should be same which is 8
As each piece is of different length so the numerator of each piece will be different.
But the total of the numerator should be 6
So the numerators will be 1, 2 and 3
Since 1 + 2 + 3 = 6
So length of each piece will be
[tex] \frac{1}{8} [/tex] yard
[tex] \frac{2}{8} [/tex] yard
and [tex] \frac{3}{8} [/tex] yard
