Respuesta :
1. Let's call:
x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).
2. The area of a rectangle is:
A=(b)(h)
b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)
3. Then, we have a quadratic equation:
924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0
4. We apply the quadratic formula to find the value of "x":
x=(-b±√(b^2-4ac))/2a
x=3.71
The answer is: The width of the walkway is 3.71 ft
x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).
2. The area of a rectangle is:
A=(b)(h)
b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)
3. Then, we have a quadratic equation:
924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0
4. We apply the quadratic formula to find the value of "x":
x=(-b±√(b^2-4ac))/2a
x=3.71
The answer is: The width of the walkway is 3.71 ft
The width of the walway is 3.71 ft.
Step-by-step explanation:
Given :
Area = 924 [tex]\rm ft^2[/tex]
The pool is 16 feet by 32 feet.
Solution :
let x be width of the walkway.
There is a width of the walkway on each side of the pool therefore,
base, b = 2x + 16
width, w = 2x + 32
Now, the entire area of the pool including the walkaway is,
[tex]\rm 924 = b\times w[/tex]
[tex]924 = (2x+16)\times(2x+32)[/tex]
[tex]4x^2+64x+32x+512=924[/tex]
[tex]x^2+24x-103=0[/tex]
[tex]x =\dfrac{ -24\pm\sqrt{576+412} }{2}[/tex]
[tex]x = 3.71[/tex]
The width of the walway is 3.71 ft.
For more information, refer the link given below
https://brainly.com/question/15190643?referrer=searchResults