Respuesta :
There is only one pressure this situation would be a "constant pressure" process
Answer:
W = [tex]-8.1 * 10^{-2} J[/tex]
Explanation:
The rest of the question actually states that:
**If the average net pressure is 1.5x10^3Pa and the balloons volume increases by 5.4x10^-5 m^3, how much work is done by the expanding gas.**
Work done, W against an external pressure, [tex]P_{ext}[/tex], which causes a change in volume, ΔV of an object is given as:
[tex]W = -P_{ext}[/tex] ΔV
[tex]P_{ext}[/tex] = [tex]1.5 * 10^5 Pa[/tex]
ΔV = [tex]5.4 * 10^{-5} m^3[/tex]
=> [tex]W = -1.5 * 10^3 * 5.4 * 10^{-5}\\\\W = -8.1 * 10^{-2} J[/tex]
Note: The negative sign denotes that the work is done against external pressure.
