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The dilation rule DF,3(x, y) is applied to △ABC, where the center of dilation is at F(1, 1). The distance in the x-coordinates from A(–2, 2) to the center of dilation F(1, 1) is unit(s). The distance in the y-coordinates from A(–2, 2) to the center of dilation F(1, 1) is unit(s). The vertex A' of the image is .

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Answer:

The distance between x-coordinates of A and F is 3 units.The distance between y-coordinates of A and F is 1 unit. The coordinates of A' are (-8,4).

Step-by-step explanation:

The dilation rule is [tex]D_{F,3}(x,y)[/tex].

It means the center of dilation is F and scale factor is 3.

The coordinates of A are (-2,2) and the coordinates of F are (1,1).

The distance in the x-coordinates from A(–2, 2) to the center of dilation F(1, 1) is

[tex]-2-1=-3[/tex]

The distance can not be negative. So, the distance between x-coordinates of A and F is 3 units.

The distance in the y-coordinates from A(–2, 2) to the center of dilation F(1, 1) is

[tex]2-1=1[/tex]

The distance between y-coordinates of A and F is 1 unit.

According to given dilation rule,

[tex](x,y)\rightarrow (3(x-1)+1,3(y-1)+1)[/tex]

The coordinates of A' are

[tex]A(-2,2)\rightarrow A'(3(-2-1)+1,3(2-1)+1)[/tex]

[tex]A(-2,2)\rightarrow A'(3(-3)+1,3(1)+1)[/tex]

[tex]A(-2,2)\rightarrow A'(-8,4)[/tex]

Therefore the distance between x-coordinates of A and F is 3 units.The distance between y-coordinates of A and F is 1 unit. The coordinates of A' are (-8,4).

Answer:

3

1

(-8,4)    

Step-by-step explanation:

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