Answer:
Lateral surface area of pyramid is 768 [tex]cm^2[/tex]
Step-by-step explanation:
Given: Pyramid with Square base.
Side of square = 24 cm
Slant height = 16 cm
To find: Lateral surface area of pyramid
Figure of pyramid is attached.
Pyramid with square base has triangle in sides.
∴Lateral surface are of Pyramid = sum of area of all triangles
slant height of pyramid becomes height of triangle and side of square becomes base of triangle. Also all traingle are on equal side so, they have equal area.
Area of triangle =[tex]\frac{1}{2}\timesbase\timesheight[/tex]
⇒ Lateral surface area of pyramid = 4 × area of triangle
Lateral surface area of triangle = [tex]4\times\frac{1}{2}\timesbase\timesheight[/tex]
Base of triangle, AB = 24 cm and Height of triangle, OM = 16 cm
putting these value we get,
Lateral Area of Pyramid = [tex]4\times\frac{1}{2}\times24\times16[/tex]
= 768 [tex]cm^2[/tex]
Therefore, Lateral surface area of pyramid is 768 [tex]cm^2[/tex]
