We want to find 3 consecutive integers such that their sum is equal to 327.
We will see that the integers are: 108, 109, and 110.
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Let's see how we can define consecutive integers.
If N is the first integer, then the next one will be N + 1, and the next one will be N + 2.
Thus the sum of 3 consecutive integers can be written as:
N + (N + 1) + (N + 2)
And that sum must be equal to 327, so we can write:
N + (N + 1) + (N + 2) = 327
Now we must solve this for N:
N + (N + 1) + (N + 2) = 327
3*N + 3 = 327
3*N = 327 - 3 = 324
N = 324/3 = 108.
Then the first integer is 108.
The next one is 109, and the final one is 110.
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