Respuesta :

[tex] \sqrt{64y^{16}}= \sqrt{(8y^{8})^2}=8y^8[/tex]

The square root of the given algebraic expression [tex]64y^{16}[/tex] is [tex]\bold{8y^8}[/tex]

What is an algebraic expression?

"It is a mathematical statement which consists of numbers, variables and mathematical operations."

For given question,

We have been given an algebraic expression [tex]64y^{16}[/tex]

We need to find the square root of given algebraic expression.

[tex]\Rightarrow \sqrt{ 64y^{16}}\\\\= \sqrt{ 64\times y^{16}} \\\\=\sqrt{64} \times \sqrt{y^{16}} \\\\=8\times (y^{16})^{\frac{1}{2} }\\\\=8\times y^{\frac{16}{2} }\\\\= 8\times y^8[/tex]

Therefore, the square root of the given algebraic expression [tex]64y^{16}[/tex] is [tex]\bold{8y^8}[/tex]

Learn more about the algebraic expression here:

https://brainly.com/question/19245500

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