Answer:
the perimeter is [tex]8\sqrt{2} +2\sqrt{10}[/tex]
Step-by-step explanation:
It is given that PQRS is a parallelogram
with sides SR=[tex]4\sqrt{2}[/tex] and QR = [tex]\sqrt{10}[/tex]
We know that the opposite sides in a parallelogram are equal
so we have
PQ= SR= [tex]4\sqrt{2}[/tex]
PS= QR= [tex]\sqrt{10}[/tex]
Now to find the perimeter of parallelogram we add all the sides
perimeter = [tex]PQ+SR+PS+QR[/tex]
=[tex]4\sqrt{2} +4\sqrt{2} +\sqrt{10} +\sqrt{10}[/tex] ( plug the values)
=[tex]8\sqrt{2} +2\sqrt{10}[/tex]
hence the perimeter is [tex]8\sqrt{2} +2\sqrt{10}[/tex]
