MATH HELP PLEASE WILL GIVE BRAINLIEST!!
What is the trigonometric ratio for cosN ?

Enter your answer, as a simplified fraction, in the boxes.

MATH HELP PLEASE WILL GIVE BRAINLIEST What is the trigonometric ratio for cosN Enter your answer as a simplified fraction in the boxes class=

Respuesta :

cos n=A/H=36/39
=12/13

THERFORE, COS N=12/13
aachen

Given is a Right triangle LMN with right angle at M i.e. angle M = 90 degrees.

Given are the sides LM = 15, MN = 36, and LN = 39.

It says to find cos(N) = ?

So opposite side would be LM, adjacent side would be MN, and LN is the hypotenuse.

We know about the "Soh-Cah-Toa" rule in which cosine ratio is given by :-

[tex] cos(N) = \frac{Adjacent}{Hypotenuse} \\\\
cos(N) = \frac{MN}{LN} \\\\
cos(N) = \frac{36}{39} \\\\
cos(N) = \frac{12}{13} [/tex]

Hence, final answer is [tex] cos(N) = \frac{12}{13} [/tex].