Answer: The correct probability is (D) [tex]P(C/A)=\dfrac{13}{17}.[/tex]
Step-by-step explanation: We are given to select the option that gives the correct probability statements using the Venn-diagram in the figure.
From the figure, we can see that there are three events, A, B and C.
And,
[tex]n(A)=1+6+7+3=17,\\\\n(B)=1+6+4+9=20,\\\\n(C)=6+4+6+7=23,\\\\n(A\cap B)=1+6=7,\\\\n(A\cap C)=6+7=13,\\\\n(B\cap C)=6+4=10,\\\\n(A\cap B\cap C)=6.[/tex]
By the law of SET THEORY, we have
[tex]n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cup B\cup C)=17+20+23-7-13-10+6\\\\\Rightarrow n(A\cup B\cup C)=36.[/tex]
So, the total number of elements in the sample space 'S' will be
n(S) = 36 + 8 = 44.
Therefore,
[tex]P(A/B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{\dfrac{n(A\cap B)}{n(S)}}{\dfrac{n(B)}{n(S)}}=\dfrac{7}{44}\times \dfrac{44}{20}=\dfrac{7}{20},\\\\\\\\P(B/A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{\dfrac{n(B\cap A)}{n(S)}}{\dfrac{n(A)}{n(S)}}=\dfrac{7}{44}\times \dfrac{44}{17}=\dfrac{7}{17},\\\\\\\\P(A/C)=\dfrac{P(A\cap C)}{P(C)}=\dfrac{\dfrac{n(A\cap C)}{n(S)}}{\dfrac{n(C)}{n(S)}}=\dfrac{13}{44}\times \dfrac{44}{23}=\dfrac{13}{23},\\\\\\\\P(C/A)=\dfrac{P(C\cap A)}{P(A)}=\dfrac{\dfrac{n(C\cap A)}{n(S)}}{\dfrac{n(A)}{n(S)}}=\dfrac{13}{44}\times \dfrac{44}{17}=\dfrac{13}{17}.[/tex]
Thus, the correct probability is [tex]P(C/A)=\dfrac{13}{17}.[/tex]
Option (D) is correct.
The probability P(A/B) is 7/20, the probability P(B/A) is 7/17, the probability P(A/C) is 13/23, and the probability is P(C|A) is 13/17 option fourth is correct.
It is defined as the diagram that shows a logical relation between sets.
The Venn diagram consists of circles to show the logical relation.
For the value of probability P(A|B):
We know that:
[tex]\rm P(A/B)=\frac{P(A\cap B)}{P(B)} \Rightarrow \frac{\frac{n(A\cap B)}{n(T)} }{\frac{n(B)}{n(T)} }[/tex]
From the Venn diagram:
n(A∩B) = 7, n(B) = 20, n(T) = 44
P(A/B) = (7/44)×44/20)
P(A/B) = 7/20
For P(B|A):
[tex]\rm P(B/A)=\frac{P(B\cap A)}{P(A)} \Rightarrow \frac{\frac{n(B\cap A)}{n(T)} }{\frac{n(A)}{n(T)} }[/tex]
The values of n(B∩A) = 7, n(A) =17
P(B/A) = (7/44)×(44/17)
P(B/A) = 7/17
For P(A|C):
[tex]\rm P(A/C)=\frac{P(A\cap C)}{P(C)} \Rightarrow \frac{\frac{n(A\cap C)}{n(T)} }{\frac{n(C)}{n(T)} }[/tex]
The value of n(A∩C) = 13, n(C) = 23
P(A/C) = (13/44)×(44/23)
P(A/C) = 13/23
For P(C|A):
[tex]\rm P(C/A)=\frac{P(C\cap A)}{P(A)} \Rightarrow \frac{\frac{n(C\cap A)}{n(T)} }{\frac{n(A)}{n(T)} }[/tex]
The values of n(C∩A) = 13, n(A) = 17
P(C|A) = (13/44)×(44/17)
P(C|A) =13/17
Thus, the probability P(A/B) is 7/20, the probability P(B/A) is 7/17, the probability P(A/C) is 13/23, and the probability is P(C|A) is 13/17 option fourth is correct.
Learn more about the Venn diagram here:
brainly.com/question/1024798
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