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#1: A gas effuses 4.0 times faster than oxygen (O2). What is the molecular mass of the gas?

A. 1.0 g/mol

B. 2.0 g/mol

C. 4.0 g/mol

D. 7.67 g/mol

**not sure... i think it's either B or C... what do u thinK? @Mertsj :),

Respuesta :

W0lf93
From Graham's law of diffusion
R1/R2 = √M2/M1 where R1 and R2 is the rate of diffusion of Oxygen and
unknown gas respectively
M1 and M2 is the molar mass of Oxygen and unknown gas respectively 
So R2 = 4 * R1
M1 = 32 and M2 = ?
So we have R1/ 4 R1 = √ x/32
(1/16) = x/32
X = 32 /16 = 2 g/mol


samueladesida43

If a gas effuses 4.0 times faster than oxygen (O2), the molecular mass of the gas is 2.0 g/mol.

HOW TO USE GRAHAM LAW OF DIFFUSION?

The molecular mass of a gas can be calculated using Graham's equation of diffusion as follows:

R1/R2 = √M2/M1

  • Where R1 and R2 are the rate of diffusion of oxygen and unknown gas respectively
  • M1 and M2 is the molecular mass of oxygen and unknown gas respectively

Since the gas effuses 4.0 times faster than oxygen;

  • R1 = ?
  • R2 = 4R1
  • M1 = 32g/mol
  • M2 = ?

R1/4R1 = ✓32/M2

(1/16) = x/32

16x = 32

x = 2g/mol

Therefore, If a gas effuses 4.0 times faster than oxygen (O2), the molecular mass of the gas is 2.0 g/mol.

Learn more about Graham's law of diffusion at: https://brainly.com/question/2681511

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