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Four wires meet at a junction. it is assumed that two currents, i1 and i4, enter the node. an ammeter records a value of +4a for i1. currents i2 and i3 are travelling out of the node. i2 has 3a running through it, and i3 has 0.5 a running through it. what is the current in i4?

Respuesta :

Rodiak
Kirchhoff’s Current Law states that sum of entering currents is equal to sum of exiting currents.
[tex] I_{IN} = I_{OUT} [/tex]

We are given information:
[tex] I_{1} = 4A \\ I_{2} = 3A \\ I_{3} =0.5A \\ I_{4} = ?[/tex]

Kirchhoff’s Current Law for our example is:
[tex] I_{1} + I_{4} = I_{2} + I_{3} [/tex]
[tex] 4 + x = 3 + 0.5 [/tex]
[tex] 4 + x = 3.5 [/tex]
[tex] x = -0.5A [/tex]

We got negative value for current. This means that current I₄ is not entering but it is leaving from the junction.

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