Respuesta :
Solution:
workdone = change in potential energy
W = Force times distance
= ( m -dm)g • ( x)
= mgx -(dm(gx))
= (15 × 10 × 15) -(6/15 gx.dx)
=2250 - (6/15 x10x 225/2)
=2250 - (3 x 15x 10)
= 2250 - 450
= 1800 Joule
The answer is 1800 Joules.
workdone = change in potential energy
W = Force times distance
= ( m -dm)g • ( x)
= mgx -(dm(gx))
= (15 × 10 × 15) -(6/15 gx.dx)
=2250 - (6/15 x10x 225/2)
=2250 - (3 x 15x 10)
= 2250 - 450
= 1800 Joule
The answer is 1800 Joules.
The work done in pulling a bucket full of water with a weight of 15 kg that lost 6 kg of it from the hole from a well 15 m deep is 1350 Joules
Further Explanation;
Work done
- Work done refers to the measure of energy when a body is moved by a force through a certain distance.
- Work done is therefore equivalent to energy transferred.
- Work done is given by the product of force acting on an object and distance moved by the object.
- Therefore; Work done = Force × distance
- Force refer to a pull or a push and is measured in Newtons, N.
- Distance is measured in meters, m.
Thus; Work done is measured in Joules, J, or Nm
In this case;
Mass of the bucket is 15 Kg
However, 6 kg of water flew out due to the whole, therefore the remaining mass is 9 kg.
Force or Weight = Mass (kg) × 10 N/kg
Therefore;
Force = 90 Newtons
Distance = 15 m
Therefore;
Work done = 90 N × 15 m
= 1350 Joules
Hence; Work done pulling out the bucket from the well is 1350 Joules.
Key words: Work done, Force, Distance
Learn more about;
- Work done; https://brainly.com/question/12029835
- Force: https://brainly.com/question/11368524
- Example of work done: https://brainly.com/question/12029835
Level: High school
Subject: Physics
Topic: Work, power and simple machines
