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The force in Newtons on a particle directed along the x-axis is given by F(x)=exp(−(x/2)+6) for x≥0 where x is in meters. The particle is constrained to move along the x-axis. Find the work done in Joules on the particle, W, in moving it from x=0 to x=1 using the fact that F=dW/dx. For your reference, 1 Joule = 1 Newton × 1 meter.,

Respuesta :

meerkat18

To find the work done on the particle, the following is the solution:

Dw = F dx

W = integral over the path ( F(x) dx)

W = integral from 0 to 1 (e^(-x/5 + 5) dx)

W = -5e^(-x/5 + 5) from 0 to 1

W = 135 J

The work done is 135 J.

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