Respuesta :
The sum would be written as:
[tex]\Sigma_{n=1}^{5} (3n-2)[/tex]
It goes from n=1 to =5 because it is the first 5 terms of the sum.
The sequence has a first term, a₁, of 1. The common difference, d, is 3. The explicit formula would then be:
[tex]a_n=1+3(n-1)[/tex]
Using the distributive property to simplify, we would have:
[tex]a_n=1+3n-3 \\a_n=3n-2[/tex]
[tex]\Sigma_{n=1}^{5} (3n-2)[/tex]
It goes from n=1 to =5 because it is the first 5 terms of the sum.
The sequence has a first term, a₁, of 1. The common difference, d, is 3. The explicit formula would then be:
[tex]a_n=1+3(n-1)[/tex]
Using the distributive property to simplify, we would have:
[tex]a_n=1+3n-3 \\a_n=3n-2[/tex]
Using sigma notation, the sum is expressed as:
[tex]\sum_{i = 0}^{4} 1 + 3n[/tex]
In the given sum, we have that:
- The first term is 1.
- The difference between consecutive terms is 3.
- There are 5 terms, with indexes ranging from 0 to 5 - 1 = 4.
Hence, the sum, in sigma notation, can be modeled by:
[tex]\sum_{i = 0}^{4} 1 + 3n[/tex]
A similar problem is given at https://brainly.com/question/16599038
