Respuesta :

fluffypringle
1/f=1/object distance + 1/image distance so if we flip this around and get 1/f - 1/object distance which when we plug in values we get 1/10cm - 1/20 we get 1/20 for image which means the image appears 20 cm away from the lens
okpalawalter8

The image distance and magnification is mathematically given as

  • i2= - 24.6 cm
  • M= -2.69

What are the image distance and magnification?

Question Parameter(s):

An object is placed 20.0 cm from the front of

a converging lens of focal length 10.0 cm.

Generally, the equation for the lens equation   is mathematically given as

1 / i + 1 / o = 1 / f

Therefore

i = o f / (o - f)

i1 = 30 * 15.2 / (30 - 15.2)

i1= 30.8 cm

Therefore

i2 = 9.4 * 15.2 / (9.4 - 15.2)

i2= - 24.6 cm

In conclusion, magnification

M = m1 * m2

M= (-30.8 / 30) * (24.6 / 9.4)

M= -2.69

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