You select a family with four children. if m represents a male child and f a female​ child, the set of equally likely outcomes for the​ children's genders is​ {ffff, fffm,​ ffmf, fmff,​ mfff, mffm,​ mfmf, mmff,​ ffmm, fmfm,​ fmmf, fmmm,​ mfmm, mmfm,​ mmmf, mmmm}. find the probability of selecting a family with exactly three male children

Respuesta :

There are 16 possible events. 4 of them involve the event of having exactly 3 male children, so the probability is [tex]\dfrac4{16}=\dfrac14[/tex].

Answer with explanation:

Number of children in the family = 4

It is also given that, f represents female child and m represents male child.

Total Possible outcome ={ffff, fffm,​ ffmf, fmff,​ mfff, mffm,​ mfmf, mmff,​ ffmm, fmfm,​ fmmf, fmmm,​ mfmm, mmfm,​ mmmf, m m mm}=16

Total favorable outcome = Selecting a family with exactly three male children

           =  { fmmm,​ mfmm, mmfm,​ mmmf}=4

Probability of an event

         [tex]=\frac{\text{Total favorable outcome}}{\text{Total Possible outcome}}\\\\=\frac{4}{16}\\\\=\frac{1}{4}[/tex]

or there is other way of looking at this question.

If a family has only three children, then

Total possible Outcome =1 +1+3+3=8 possible outcome={f ff,f m f,f f m,m ff,m m f,m f m,f mm,m mm}

Total favorable outcome ={m mm}=1

Probability of an event

         [tex]=\frac{\text{Total favorable outcome}}{\text{Total Possible outcome}}\\\\\frac{1}{8}[/tex]