Respuesta :
Each bulb and the labor to install it costs
.. $6.95 +$3 = $9.95
100 bulbs and 10 years totals (100*10) = 1000 bulb·years. For the price of $9.95, you purchase 5 bulb·years, so the total cost for 1000 bulb·years is
.. (1000 b·y)*($9.95/(5 b·y)) = $1990
Over a 10-year period, installation and replacement of 200 bulbs in 100 lamps will cost $1990. Then the per-year cost is ...
.. $1990/(10 yr) = $199/yr
.. $6.95 +$3 = $9.95
100 bulbs and 10 years totals (100*10) = 1000 bulb·years. For the price of $9.95, you purchase 5 bulb·years, so the total cost for 1000 bulb·years is
.. (1000 b·y)*($9.95/(5 b·y)) = $1990
Over a 10-year period, installation and replacement of 200 bulbs in 100 lamps will cost $1990. Then the per-year cost is ...
.. $1990/(10 yr) = $199/yr
Answer: $200.00
Step-by-step explanation:
$6.95+ $3.00= $19.90
$19.90 * 100= $1,990
$1,990 / $9.95 = $200.00
take the orginal cost 6.95 plus the $3 labor which equals 19.90 then you multiply by the number of bulbs 100 which equals 1990 then divide 1990 by the cost of bulbs 9.95 which equals 200!