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37 packages are randomly selected from packages received by a parcel service. The sample has a
mean weight of 10.3 pounds and a standard deviation of 2.4 pounds. What is the 95% confidence
interval for the true mean weight, µ, of all packages received by the parcel service?

Respuesta :

jushmk
True mean = mean+/- Z*(SD/sqrt (n))

Where
Z = 1.96 at 95% confidence interval
Mean = 10.3 pounds
SD = standard deviation = 2.4 pounds
n= sample size = 37 packages

Substituting;
True mean range = 10.3+/- 1.96 * 2.4/Sqrt (37) =10.3+/- 0.77 = 9.53<mean<11.07

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