The probability is 0.0322.
This can be modeled using a binomial distribution; each probability is independent, there is a fixed number of trials, and there are two outcomes (success or failure).
[tex]_nC_r(p)^r(1-p)^{n-r}
\\
\\=_5C_3(\frac{1}{6})^3(\frac{5}{6})^2=10(\frac{1}{6})^3(\frac{5}{6})^2=0.0322[/tex]
