A cord of mass 0.65 kg is stretched between two supports 28 m apart. if the tension in the cord is 150 n, 2 how long will it take a pulse to travel from one support to the other?

Ans: Time taken by a pulse to travel from one support to the other = 0.348s

Explanation:
First you need to find out the speed of the wave.

Since
Speed = v = [tex] \sqrt{ \frac{T}{\mu} } [/tex]

Where
T = Tension in the cord = 150N
μ = Mass per unit length = mass/Length = 0.65/28 = 0.0232 kg/m

So
v = [tex] \sqrt{ \frac{150}{0.0232} }[/tex] = 80.41 m/s

Now the time-taken by the wave = t = Length/speed = 28/80.41=0.348s

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snehashish65 snehashish65 · Answer 2 · 2021-10-25T17:24:24+02:00

The time taken by the pulse to travel from one support to the other is 0.348 s.

Given data:

The mass of cord is, m = 0.65 kg.

The distance between the supports is, d = 28 m.

The tension in the cord is, T = 150 N.

The time taken by the pulse to travel from one support to the other is given as,

[tex]v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\[/tex]

Here, v is the linear velocity of pulse. Its value is,

[tex]v = \sqrt{\dfrac{T \times d}{m} } \\v = \sqrt{\dfrac{150 \times 28}{0.65}}\\\\v = 80.38 \;\rm m/s[/tex]

Then,

[tex]t=\dfrac{28}{80.38}\\\\t = 0.348 \;\rm s[/tex]

Thus, the time taken by the pulse to travel from one support to the other is 0.348 s.

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