Respuesta :
y = 0.08x2-1.6x+13 and y = 0.08(x-10)2+5 is the correct answer :)
Answer : y = [tex] 0.08x^2 - 1.6x + 13 [/tex] and y= [tex] 0.08 (x- 10)^2 + 5 [/tex]
Sandi skates along a path that can be modeled by the equation
y = [tex] 0.08x^2 - 1.6x + 13 [/tex]
David starts at (20, 13) and skates along a path that can be modeled by a quadratic function with a vertex at (10, 5).
Vertex form of quadratic function is
y = [tex] a(x-h)^2 + k [/tex] where (h,k) is the vertex
We plug in (10,5) for h and k
y= [tex] a(x-10)^2 + 5 [/tex]
Now plug in (20,13) in the above equation and find out 'a'
13 = [tex] a(20 - 10)^2 + 5 [/tex]
13 = [tex] a(10)^2 + 5 [/tex]
13 = 100 a + 5
Subtract 5 on both sides
8 = 100a
a = 0.08
When we plug in 0.08 for 'a' then the equation becomes
y= [tex] 0.08 (x- 10)^2 + 5 [/tex]
