How many grams of CaSO4 (Molar mass = 136 g) can be produced if 15.4 g Ca3(PO4)2 (molar mass = 310 g) completely reacts?

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13-04-2018
Chemistry

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How many grams of CaSO4 (Molar mass = 136 g) can be produced if 15.4 g Ca3(PO4)2 (molar mass = 310 g) completely reacts?

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transitionstate transitionstate · Answer 1 · 2018-04-25T00:13:14+02:00

Balance Chemical equation is as follow,

Ca₃(PO₄)₂ + 3 H₂SO₄ → 3 CaSO₄ + 2 H₃PO₄

According to eq.

310 g (1 mole) of Ca₃(PO₄)₂ produces = 408.42 g (3 mole) of CaSO₄
So,
15.4 g of Ca₃(PO₄)₂ will produce = X g of CaSO₄

Solving for X,
X = (15.4 g × 408.42 g) ÷ 310 g

X = 20.28 g of CaSO₄