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The figure shown has a parallelogram on top and a rectangle below it:

A figure has a rectangular portion, and above the rectangle there is a parallelogram. The length of the rectangle is 42.4 inches, the width of the rectangle is 10.5 inches, and the height of the parallelogram is 12.2 inches.

What is the total area of the figure?

please pick from the four below

445.20 square inches

517.28 square inches

724.50 square inches

962.48 square inches

The figure shown has a parallelogram on top and a rectangle below it A figure has a rectangular portion and above the rectangle there is a parallelogram The len class=

Respuesta :

the total area of the figure should be 962.48 square inches
calculista

Answer:

The area of the figure is [tex]962.48\ in^{2}[/tex]

Step-by-step explanation:

we know that

The area of the figure is equal to the area of parallelogram plus the area of rectangle

Step 1

Find the area of rectangle

The area of rectangle is equal to

[tex]A=LW[/tex]

we have

[tex]L=42.4\ in[/tex]

[tex]L=10.5\ in[/tex]

substitute

[tex]A=42.4*10.5=445.2\ in^{2}[/tex]

Step 2

Find the area of parallelogram

The area of parallelogram is equal to

[tex]A=bh[/tex]

we have

[tex]b=42.4\ in[/tex]

[tex]h=12.2\ in[/tex]

substitute

[tex]A=42.4*12.2=517.28\ in^{2}[/tex]  

step 3

Find the area of the figure

[tex]445.20\ in^{2}+517.28\ in^{2}=962.48\ in^{2}[/tex]

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