Answer:
2 Hz
Explanation:
The frequency of a wave is equal to the reciprocal of its period:
[tex]f=\frac{1}{T}[/tex]
where T is the period of the wave.
The period of a wave corresponds to the time it takes for one complete oscillation of the wave to pass a given point. In this problem, one complete wave passes the pile in 0.50 s, so the period of the wave is T = 0.50 s. Therefore, the frequency is:
[tex]f=\frac{1}{T}=\frac{1}{0.50 s}=2 Hz[/tex]
