jbeno23
contestada

Compare the functions shown below:


f(x)

cosine graph with points at 0, negative 1 and pi over 2, 1 and pi, 3 and 3 pi over 2, 1 and 2 pi, negative 1
g(x)

x y
−6 −11
−5 −6
−4 −3
−3 −2
−2 −3
−1 −6
0 −11
h(x) = 2 cos x + 1


Which function has the greatest maximum y-value?

a. f(x)
b. g(x)
c. g(x) and h(x)
d. f(x) and h(x)

Respuesta :

CarlosRCR
We can find the local maxima and minima of any -continous- function by first finding where the slope is 0, as at this point maxima or minima exist.

Given an arbitrary function '[tex]f(x)[/tex]' we find the point of slope 0 by taking its first derivative and equaling to 0 ('[tex] \frac{d}{dx}f(x)=0 [/tex]').

Lets, first, find the local extremes of the first function:
[tex]f(x)=cos(x)[/tex]
[tex] \frac{d}{dx} f(x)=\frac{d}{dx}cos(x)=-sin(x)=0[/tex]
[tex]x=sin^{-1} (0)=0[/tex]

So our first function has a maxima at '[tex]x=0[/tex]' or at '[tex]y=f(0)=cos(0)=1[/tex]'.

Now we get the extremes for the second function:
[tex]h(x)=2cos(x)+1[/tex]
[tex]\frac{d}{dx} h(x)=\frac{d}{dx}[2cos(x)+1]=-2sin(x)=0[/tex]
[tex]x=0[/tex]

So our second function has a maxima at '[tex]x=0[/tex]' or at '[tex]y=h(0)=2cos(0)+1=3[/tex]'.

Clearly, '[tex]h(0)=3\ \textgreater \ f(0)=1[/tex]', this means the second function '[tex]h(x)[/tex]' has the largest maxima -y value-.


annaroseurban

Answer:

f(x) and h(x)

Step-by-step explanation:

f(x) and h(x) have the greatest maximum y-value because if you graph out all the equations you can determine by graph which ones have the greatest y-value. When you graph the equations you find that f(x) and h(x) both have a greatest y-value of 3! While g(x) has a greatest y-value of -2.

*Please note that it is looking for the greatest y-VALUE not the greatest y-INTERCEPT.

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