A fair, twenty-faced die has $19$ of its faces numbered from $1$ through $19$ and has one blank face. another fair, twenty-faced die has $19$ of its faces numbered from $1$ through $8$ and $10$ through $20$ and has one blank face. when the two dice are rolled, what is the probability that the sum of the two numbers facing up will be $24?$ express your answer as a common fraction.

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08-06-2018
Mathematics

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A fair, twenty-faced die has $19$ of its faces numbered from $1$ through $19$ and has one blank face. another fair, twenty-faced die has $19$ of its faces numbered from $1$ through $8$ and $10$ through $20$ and has one blank face. when the two dice are rolled, what is the probability that the sum of the two numbers facing up will be $24?$ express your answer as a common fraction.

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frika frika · Answer 1 · 2018-06-17T22:12:59+02:00

Represent 24 as a sum of two numbers, first number from first die and second number from second die.
24=19+5=18+6=17+7=16+8=14+10=13+11=12+12=11+13=10+14=9+15=8+16=7+17=6+18=5+19=4+20 (the sums 15+9 and 20+4 are absent, because there aren't numbers: 20 on the first die and number 9 on the second die). Totally, you receive 15 different representations of 24.
The probability that the sum of the two numbers facing up will be 24 is

[tex]P= \frac{15}{20\cdot 20} = \frac{3}{80} [/tex] (here [tex]20\cdot 20[/tex] means that you have 20 possibilities to roll first number or blank face on the first die and 20 possibilities to roll number or blank face on the second die).